Amazingphilid
Answered


PLEASE HELP!!! THERE IS A PICTURE ATTACHED
Francisco is playing a game with 3 green, 2 yellow, 4 red, and 3 black marbles in a bag. He has calculated the probability of drawing a yellow marble, not replacing it, and then drawing a red marble. Explain the error in his solution.(the picture is Fransisco's work)

PLEASE HELP THERE IS A PICTURE ATTACHED Francisco Is Playing A Game With 3 Green 2 Yellow 4 Red And 3 Black Marbles In A Bag He Has Calculated The Probability class=

Sagot :

Well, the problem is that he does not replace the first marble after he draws it. Therefore, yes, he has a 2/12 probability of drawing a yellow marble first, but then he has a 4/11 probability of drawing a red marble second, not 4/12. This is because there are going to only be 11 marbles left in the bag after he draws the first marble and does not replace it.

The correct answer would be:
(2/12)(4/11)=8/132=4/66=2/33
MissLorweeid

Answer:

Step-by-step explanation:

ample Response: The events are dependent, so the sample space changes for the second draw. After drawing the first marble, there are only 11 marbles left. The probability is (  

2

12

) (  

4

11

)  =  

8

132

, or  

2

33

.

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