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Rewrite y= x^2-6x+2 in vertex form and state the coordinates of the vertex

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Damientseid
because Vertex form is f(x)=a(x-h)[tex] ^{2} [/tex]+k, when (h,k) in the vertex

and y= [tex] x^{2} -6x+2 = x^{2} -6x+9-7 = (x-3) ^{2} -7[/tex]

so [tex]y= (x-3) ^{2} -7 [/tex] will be the vertex form

so the vertex will be (3,-7)

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