Kevin can carry a basket 5 feet. Rachel can carry it 3 feet farther than kevin. Daniel can carry the basket half as far as Rachel. Is it reasonable to say that they can carry it 15 feet with each person taking only one turn?

Sagot :

No beause 5+8+4=17 and 17> 15 by 2. So they can carry it 17 feet with each person taking 1 turn. Hope I helped!

Let

x--------> distance that Kerry can carry the basket in feet

y--------> distance that Rachel can carry the basket in feet

z------->  distance that Daniel can carry the basket in feet

we know that

[tex] x=5\ ft[/tex] -------> equation [tex] 1 [/tex]

[tex] y=x+3[/tex] -------> equation [tex] 2 [/tex]

[tex] z=(y/2)[/tex] -------> equation [tex] 3 [/tex]

Substitute equation [tex] 1 [/tex] in equation [tex] 2 [/tex]

[tex] y=5+3[/tex]

[tex] y=8\ ft[/tex]

Find the value of z

[tex] z=(8/2)=4\ ft[/tex]

if each person taking only one turn,

then

the distance that they can carry the basket is equal to  ------> x+y+z

[tex] (5+8+4)=17\ feet[/tex]

[tex] 17\ feet > 15 \ feet[/tex]

therefore

the answer is

Yes It is reasonable