Sagot :
110, because it's the only common multiple of both 2 and 5 between 108 and 118.
Answer:
The number would be 110.
Step-by-step explanation:
Since, both 2 and 5 are common factors of a number.
Then the number must be divisible or multiple of LCM(2, 5) i.e. 10,
Now, the numbers is between 101 and 118.
102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118
Since, only 110 is multiple of 10,
Hence, the required number which has both 2 and 5 as its factor is 110.