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Roses sell for $3 each and carnations for$1.50 each. If a mixed bouquet of 20 flowers consisting of roses and carnations cost $39 how many of each type of flower is in the bouquet?

Sagot :

LHurrawid
3x + 1.50y = 39

12 Roses     2 Carnations

3(12) + 1.50(2) = 39
36 + 3 = 39
39=39

The number of roses in the bouquet is 6 and the number  carnations is 14.

of Two simultaneous equations can be gotten from the question:

3r + 1.5c = 39 equation 1

r + c = 20 equation 2

Where:

r = number of roses

c = number of carnations

In order to determine the value of c, take the following steps:

Multiply equation 2 by 3

3r + 3c = 60 equation 3

Subtract  equation 1 from 3

1.5c = 21

Divide both sides of the equation by 1.5

c = 14

Substitute for c in equation 2

r + 14 = 20

r = 20 - 14

r = 6

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552

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