Sagot :
First you have to find the intercepts!
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~
Graph the intercepts by assigning the balue to y or x then after u assign u will graph it. Since it is a linear equation it might be easier so it may be a line not a parabola