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The perimeter of a rectangular is P = 2L + 2W. Solve for L if the perimeter is 220 ft and the length is 10 ft more than the width.

Sagot :

220= 2(10+x) + 2x
220= 20+2x+2x
220= 20+4x
200= 4x
50= x

if L is 10 more than W and the width= 50, than the length (L) would be 60 ft.

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