Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
[tex]velocity (v) = \frac{distance}{time} [/tex]
= [tex] \frac{100~ m}{10~seconds} [/tex]
= 10 m/s
Note that this one is the final velocity.
We also know that,
initial velocity (u) = 0 m/s ....... because the car starts from rest.
Now,
[tex]acceleration (a)= \frac{change~in~velocity}{time} [/tex]
= [tex] \frac{v-u}{t} [/tex]
= [tex] \frac{10-0}{10} [/tex]
= 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
= 1200 kg * 1 m/s²
= 1200 kg.m/s²
= 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....note that displacement is same as distance.
= 1200 N * 100 m
= 120000 N.m
= 120000 J
Now,
Power (P) = [tex] \frac{Work~done(W)}{time(t)} [/tex]
= [tex] \frac{120000~J}{10s} [/tex]
= 12000 J/s
= 12000 watt
SO,
A) The acceleration of the car is 1 m/s².
B) 1200 Newton (N) force must have acted on the car.
C) The velocity of the car after 10 seconds is 10 m/s.
D) 120000 Joule (J) work was done on the car.
E) The engine produced a minimum power of 12000 watt.
