Sagot :
[tex]3,8x + 14.5 < 32\\
3,8x<32-14,5\\
3,8x<17,5\ /:3,8\\
x<\frac{17,5}{3,8}\\
\\
17\frac12 :3\frac45=\frac{35}{2} :\frac{19}5=\frac{35}2\cdot \frac5{19}\\=\frac{175}{38}=4\frac{23}{28}\\
x<4\frac{23}{28}\\
x\in (-\infty;4\frac{23}{28})[/tex]
Answer: x < 4.6 rounded to the tenths
Step-by-step explanation:
3.8x + 14.5 < 32
subtract 14.5 on both sides.
3.8x < 17.5
divide by 3.8 on both sides.
x < 4.60526316