Mauraschmenkid
Answered

A speedy river barge bound for New Orleans, Louisiana leaves Baton Rouge at 9:00 a.m. and travels at a speed of 10 miles per hour. A rail transport freight also bound for New Orleans leaves Baton Rouge at 1:30 p.m. on the same day. The train travels at 25 miles per hour, both the barge and train will travel 100 miles to reach New Orleans. How far will the train travel before catching up to the barge?

Sagot :

okay i get it now
1) At 1.30 p.m. the barge has already traveled 4.5 X 10 = 45 miles.

To catch up it will take the train 25-10 = 15miles

James129724id

Answer:

Step-by-step explanation:

A rail transport freight train also bound for New Orleans leaves Baton Rouge at 1;30 PM on the same day. The train travels at 25 MPH and the river barge travels at 10 MPH. ... the barge leaves at 9:00 am so that would be at 9 hours past midnight. the train leaves at 1:30 pm so that would be at 13.5 hours past midnight.

ID Other Questions