Answer:
Option C is correct
[tex]x = y^2-4y+40[/tex]
Step-by-step explanation:
The standard for of the quadratic equation is given as:
[tex]x= Ay^2+By+C[/tex]
As per the statement:
The vertex form of the equation of a parabola is:
[tex]x = (y-2)^2+36[/tex]
Using identity rule:
[tex](a-b)^2 = a^2-2ab+b^2[/tex]
then;
[tex]x = y^2-4y+4+36[/tex]
⇒[tex]x = y^2-4y+40[/tex]
Therefore, the standard form of the equation is, [tex]x = y^2-4y+40[/tex]
