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Mathematics

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find four consecutive multiples of 5 whose sum is 90

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M₅+(M₅+5)+(M₅+10)+(M₅+15)=90

5M₅+ 30=90

5M₅=90-30

5M₅=60

M₅=60:5

M₅=12

M₅+5=12+5=17

M₅+10=12+10=22

M₅+15=12+15=27

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