The equation of a line is x + 5y = 12. What is the y-intercept of the line?

Sagot :

x+5y=12
5y=12-x
y=(12-x)/5
y=12/5-x/5

The intercept is 12/5
[tex] x + 5y = 12 \\ \\the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\ m \ slope , \ y \ intercept = b \\ \\5y=-x+12 \ \ /:5 \\\\y=-\frac{1}{5}+\frac{12}{5}\\\\Answer: \ y-intercept: \ b=\frac{12}{5} [/tex]