Sagot :
[tex]4x-5=7+4y\ \ |-Subtract\ 7 \ from\ both\ sides\\\\
4x-5-7=7+4y-7\\\\
4x-12=4y\ \ \ Divide\ both\ sides\ by\ 4\\\\
\frac{4x}{4}-\frac{12}{4}=\frac{4y}{4}\\\\
x-3=y\\\\Solution\ is\ y=x-3.
[/tex]
The equivalent value of y from the expression if 4x - 5 = 7 + 4y is (x-3)/4
Given the expression
4x - 5 = 7 + 4y
We need to make y the subject of the formula:
Add 5 to both sides:
4x - 5 + 5= 7 + 4y + 5
4x = 12 + 4y
Subtract 12 from both sides
4x - 12 = 12 + 4y - 12
4x - 12 = 4y
y = (4x-12)/4
y = 4(x-3)/4
y = x-3/4
Hence the equivalent value of y is (x-3)/4
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