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Write a linear equation in standard form that crosses (4, -3) and (-2, 9): 
Write a linear equation in slope-intercept form that is perpendicular to y = 3x – 4 crossing (3, 6): 
Can you please explain with some details?

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Pepe11id
Slope =(9+3)/(-2-4) = 12/-6 = -2
Y+3 = -2 (×-4)  => y=-2×+5
D is the line asked
Slope: -1/3 
D: y-6 = -1/3 (×-3) or y= -1/3× + 7

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