what is the answer to 10+7x<17


Sagot :

[tex] 10+7x<17\\ 7x<7\\ x<1[/tex]
[tex]10+7x < 17\ \ \ \ |subtract\ 10\ from\ both\ sides\\\\7x < 7\ \ \ \ \ |divide\ both\ sides\ by\ 7\\\\x < 1\\\\x\in(-\infty;\ 1)[/tex]

ID Other Questions