Sagot :
[tex]7b+5-7b-2=-8\\\\(7b-7b)+(5-2)=-8\\\\0+3=-8\\\\3=-8-FALSE\\\\no\ solutions;\ b\in\O[/tex]
A 'solution' to the equation is the value of 'b' that makes the equation
a true statement. Let's work on the equation and find it:
7b + 5 - 7b - 2 = -8
Notice that on the left side, you have 7b and -7b .
When you combine those, they make zero-b, so you can get rid of them totally.
Now the equation says + 5 - 2 = -8
Look at the left side again. +5 and -2 combine to make 3 .
Now the equation says 3 = -8
Is there some value of 'b' that can make this a true statement ?
I don't think so.
There is no solution to the original equation.
That happens, and it's OK.
a true statement. Let's work on the equation and find it:
7b + 5 - 7b - 2 = -8
Notice that on the left side, you have 7b and -7b .
When you combine those, they make zero-b, so you can get rid of them totally.
Now the equation says + 5 - 2 = -8
Look at the left side again. +5 and -2 combine to make 3 .
Now the equation says 3 = -8
Is there some value of 'b' that can make this a true statement ?
I don't think so.
There is no solution to the original equation.
That happens, and it's OK.